13[4-(3-3x)]+x=5(8x+3)-2

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Solution for 13[4-(3-3x)]+x=5(8x+3)-2 equation:


Simplifying
13[4 + -1(3 + -3x)] + x = 5(8x + 3) + -2
13[4 + (3 * -1 + -3x * -1)] + x = 5(8x + 3) + -2
13[4 + (-3 + 3x)] + x = 5(8x + 3) + -2

Combine like terms: 4 + -3 = 1
13[1 + 3x] + x = 5(8x + 3) + -2
[1 * 13 + 3x * 13] + x = 5(8x + 3) + -2
[13 + 39x] + x = 5(8x + 3) + -2

Combine like terms: 39x + x = 40x
13 + 40x = 5(8x + 3) + -2

Reorder the terms:
13 + 40x = 5(3 + 8x) + -2
13 + 40x = (3 * 5 + 8x * 5) + -2
13 + 40x = (15 + 40x) + -2

Reorder the terms:
13 + 40x = 15 + -2 + 40x

Combine like terms: 15 + -2 = 13
13 + 40x = 13 + 40x

Add '-13' to each side of the equation.
13 + -13 + 40x = 13 + -13 + 40x

Combine like terms: 13 + -13 = 0
0 + 40x = 13 + -13 + 40x
40x = 13 + -13 + 40x

Combine like terms: 13 + -13 = 0
40x = 0 + 40x
40x = 40x

Add '-40x' to each side of the equation.
40x + -40x = 40x + -40x

Combine like terms: 40x + -40x = 0
0 = 40x + -40x

Combine like terms: 40x + -40x = 0
0 = 0

Solving
0 = 0

Couldn't find a variable to solve for.

This equation is an identity, all real numbers are solutions.

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